The removal of the negatively charged electron leaves the ion with an overall positive charge because the number of protons (11) now exceeds the number of electrons (10). The electron configuration is 2-8-1, indicating two electrons in the first shell, eight in the second, and a single electron in the third and outermost shell.
How Sodium Donates an Electron to Chlorine
When examining sodium, the soft, silvery metal that reacts violently with water, the story of its reactivity and bonding is fundamentally the story of a single, unruly valence electron. This transfer creates a perfect partnership: the sodium ion (Na⁺) and the chloride ion (Cl⁻).
By losing that single valence electron, the sodium atom achieves the same electron configuration as neon, the preceding noble gas. Electron Transfer and Ionic Bonding The classic demonstration of this process is the reaction between sodium and chlorine.
How Sodium Donates an Electron to Chlorine
Within the intricate framework of matter, the behavior of the electron defines the chemical identity of every element. Property Neutral Sodium Atom (Na) Sodium Ion (Na⁺) Electron Configuration 2, 8, 1 2, 8 Charge Neutral Positive (+1) Reactivity Highly Reactive Stable in ionic Compounds Size Larger Smaller (due to loss of electron and reduced electron-electron repulsion) The Ionic Environment: Sodium in Solution and Solids.
More About Electrons in sodium ion
Looking at Electrons in sodium ion from another angle can help expand the discussion and give readers a second clear paragraph under the same section.
More perspective on Electrons in sodium ion can make the topic easier to follow by connecting earlier points with a few simple takeaways.
